Marble Slab Creamery is creating a cone-shaped paper wrapper for its new green Baby Yoda waffle cone. The wrapper should have a radius of 5 cm and a slant height of 10 cm. One location wants to offer the cones a weekend earlier, so they plan to make the cone-shaped wrappers for first 25 waffle cones sold that Saturday. About how many square cm of wrapper paper will they need?

3927 square cm

Step-by-step explanation:

We want to find the area of the lateral part of the cone with radius 5 and slant height 10. The equation needed is: L = πrl, where r is the radius and l is the slant height. Plug the given values in:

L = πrl

L = π * 5 * 10 = 50π square cm

We want 25 of these, so multiply 50π by 25:

50π * 25 ≈ 3926.99 square cm ≈ 3927 square cm

3,925 cm²

Step-by-step explanation:

Wrapper area is equal to the surface area

Curved surface area of one cone:

(pi × r × s)

3.14 × 5 × 10

157

For 25 cones:

25 × 157

3925 cm²

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier