9. A person stands at the window of a building so that his eyes are 12.6 m above the level ground. An

object is on the ground 58.5 m away from the building on a line directly beneath the person. Compute

the angle of depression of the person's line of sight to the object on the ground.

Step-by-step explanation:

Given,

Height = 12.6 m

Object distance from the person = 58.5 m

Angle of depression

Hence, angle of depression is equal to

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v