The arithmetic sequence a_ia

i



a, start subscript, i, end subscript is defined by the formula:

a_1 = 5a

1



=5a, start subscript, 1, end subscript, equals, 5

a_i = a_{i - 1} + 2a

i



=a

i−1



+2a, start subscript, i, end subscript, equals, a, start subscript, i, minus, 1, end subscript, plus, 2

Find the sum of the first 700700700 terms in the sequence.

492,800

Step-by-step explanation:

Given ith term of an arithmetic sequence as shown:

ai = a(i-1)+2

and a1 = 5

When i = 2

a2 = a(2-1)+2

a2 = a1+2

a2 = 5+2

a2 = 7

When i = 3

a3 = a(3-1)+2

a3 = a2+2

a3 = 7+2

a3 = 9

It can be seen that a1, a2 and a3 forms an arithmetic progression

5,7,9...

Given first term a1 = 5

Common difference d = 7-5= 9-7 = 2

To calculate the sum of the first 700 of the sequence, we will use the formula for finding the sum of an arithmetic sequence.

Sn = n/2{2a1+(n-1)d}

Given n = 700

S700 = 700/2{2(5)+(700-1)2}

S700 = 350{10+699(2)}

S700 = 350{10+1398}

S700 = 350×1408

S700 = 492,800

Therefore, the sum of the first 700 terms in the sequence is 492,800

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer