The City of Decatur finds that salaries for residents working in the technology sector follow an approximately normal distribution with a mean of $42,800 and a standard deviation of $8,365.

To the nearest hundredth, what Z-Score would be used to determine the percentage of residents working in the technology sector who earn more than $30,000?

- 1. 15

Step-by-step explanation:

Z score is used in statistic to calculate deviation of an observed value from mean value of sample of observation.

Mathematically it is given by

using the above formula and substituting the value of of

mean = $42,800

standard deviation = $8,365

observed value =$30,000

Z = (8,365 - 42,800) / $30,000

   =  - 34,435/ 30,000 =  - 1. 14783

  = - 1. 15 ( to the nearest hundredth)

- 1. 15  Z-Score would be used to determine the percentage of residents working in the technology sector who earn more than $30,000

i can't solve unless i know what the line is

step-by-step explanation:

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