Suppose that $77,000 is invested at 5 1/2% interest, compounded quarterly.

a) Find the function for the amount to which the investment grows after t years.

b) Find the amount of money in the account at t=0,3, 6, and 10 years.

a)

b)

The amount of money in the account at t = 0 years is $77,000.

The amount of money in the account at t = 3 years is $90,711.

The amount of money in the account at t = 6 years is $106,864.

The amount of money in the account at t = 10 years is $132,961.

Step-by-step explanation:

The compound interest formula is given by:

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

Suppose that $77,000 is invested at 5 1/2% interest, compounded quarterly.

This means that, respectively,

a) Find the function for the amount to which the investment grows after t years.

b) Find the amount of money in the account at t=0,3, 6, and 10 years.

The amount of money in the account at t = 0 years is $77,000.

The amount of money in the account at t = 3 years is $90,711.

The amount of money in the account at t = 6 years is $106,864.

The amount of money in the account at t = 10 years is $132,961.

answer is c

step-by-step explanation:

81/12=324/x

x=48