Mathematics, 07.05.2020 10:02 cw1242605
Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript x f(x) = 2(RootIndex 3 StartRoot 64 EndRoot) Superscript x f(x) = 4(RootIndex 3 StartRoot 16 EndRoot) Superscript 2 x f(x) = 4(RootIndex 3 StartRoot 64 EndRoot) Superscript 2 x
Answers: 2
![f(x)=4\sqrt[3]{16}^{2x}](/tpl/images/0652/1788/7a9e0.png)
![4\sqrt[3]{4}\approx 6.3496](/tpl/images/0652/1788/0560c.png)
![f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x](/tpl/images/0652/1788/5a3c5.png)
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Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 Start...
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