Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=83, x=45, 98 percent

Could you please explain the steps and how to get to an answer? Thank you!

The 98% confidence interval for the population proportion p is (0.4149, 0.6695).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

98% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 98% confidence interval for the population proportion p is (0.4149, 0.6695).

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