I also need help with this problem.

We will use substitution to solve this system of linear equations, as the first equation has x and y with no coefficients, which makes it easier to find one in terms of the other. We can then substitute that value in the other equation and find the values of x and y.

x = y + 5 ---> equation 1

3x + 2y = 5 ---> equation 2

From equation 1, we get the value of x as y + 5. Using the substitution method, we can find the value of y by substituting (y+5) for x in the 2nd equation.

3(y+5) + 2y = 5

3y + 15 + 2y = 5

5y = 5 - 15

5y = -10

y = -2

Subsituting this value of y in (y+5), we can find x.

x = y + 5

x = -2 + 5

x = 3

Therefore, x = 3 and y = -2.

I will also solve this using elimination method.

Let us multiply equation 1 by 2, so that we get 2y in both equations.

2x = 2y + 10

3x + 2y = 5

Let us add both the equations.

2x + 3x + 2y = 5 + 2y + 10

5x = 15 + 2y - 2y

5x = 15

x = 3

Substituting this value of x in equation 1, we get

x = y + 5

3 = y + 5

y = 3 - 5

y = -2

Therefore, x = 3 and y = -2.

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled