What is the vertex of the graph of f(x)=x^2+2x-15

F
(
x
)
=
x
2
−
2
x
−
15
f
(
x
)
=
x
2
-
2
x
-
15
Find the properties of the given parabola.
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Direction: Opens Up
Vertex:
(
1
,
−
16
)
(
1
,
-
16
)
Focus:
(
1
,
−
63
4
)
(
1
,
-
63
4
)
Axis of Symmetry:
x
=
1
x
=
1
Directrix:
y
=
−
65
4
y
=
-
65
4
Select a few
x
x
values, and plug them into the equation to find the corresponding
y
y
values. The
x
x
values should be selected around the vertex.
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x
y
−
1
−
12
0
−
15
1
−
16
2
−
15
3
−
12
xy-1-120-151-162-153-12
Graph the parabola using its properties and the selected points.
Direction: Opens Up
Vertex:
(
1
,
−
16
)
(
1
,
-
16
)
Focus:
(
1
,
−
63
4
)
(
1
,
-
63
4
)
Axis of Symmetry:
x
=
1
x
=
1
Directrix:
y
=
−
65
4
y
=
-
65
4
x
y
−
1
−
12
0
−
15
1
−
16
2
−
15
3
−
12
xy-1-120-151-162-153-12
image of graph

The answer that i got was 8/3