The square of a number is equal to 10 less than 7 times that number. What are two possible solutions

y=2 or 5

Step-by-step explanation:

let the number be y

y^2=7y-10

y^2-7y+10=0

y^2-2y-5y+10=0

y(y-2)-5(y-2)=0

(y-2)(y-5)=0

y-2=0 y-5=0

y=2 y=5

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150