The functio p(x)= x(x-5)(x-2)(x+3) has four zeros. What is the smallest zero.

x = 5 or x = 2 or x = 0 or x = -3 thus 0 is the smallest root

Step-by-step explanation:

Solve for x:

x (x - 5) (x - 2) (x + 3) = 0

Split into four equations:

x - 5 = 0 or x - 2 = 0 or x = 0 or x + 3 = 0

Add 5 to both sides:

x = 5 or x - 2 = 0 or x = 0 or x + 3 = 0

Add 2 to both sides:

x = 5 or x = 2 or x = 0 or x + 3 = 0

Subtract 3 from both sides:

x = 5 or x = 2 or x = 0 or x = -3

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.