Considering a balloon that has a volume v. it contains n moles of gas, it has an internal pressure of p, and its temperature is t. if the balloon is heated to a temperature of 15.5t while it is placed under a high pressure of 15.5p, how will the volume of the balloon changed? a. it doubles b. it stays the same c. it increases greatly d. it decreases slightly

You need to use the formula P*V = n*R*T where
P = pressure
V= volume
R = a constant(0.082 I think)
T= tempreture
n = number of moles

P*V=n*R*T

After the balloon is heated the state would be:



where 


Notice that the number of moles n and of course the constant R, stay the same.



 

So the volume of the balloon stays the same. The answer to your question is B. I hope that this is the answer that you were looking for and it has helped you.

Is there more to the question?