1 + sec 0 - tan 0 sec 0 + tan 0 +1
*: 1 - sec 0 + tan 0 - sec 0 + tan 0 - 1

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

college