1aduceti la o forma mai simpla
a) 5 la puterea 3pe 2ori 125la puterea 1pe 2ori 5la puterea minus4pe3ori25la puterea 1pe 2
b) 81 la puterea2radical din 2 ori 3 radical din 8 impartit la 27la puterea a 5radical18
2 sa se demonstreze ca numarul ( 1+radical din 2) la puterea a 2 +(1 -radical din 2 ) la puterea a doua este numar natural.
3 calculati
a ) log in baza 1pe 3 2-login baza 1 pe 2 18+ log in baza 1 pe3 3
b) lg 1 pe 2 + lg2pe3++lg9pe 10
aceste puncte sunt de clasa a x-a

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)