What two numbers have a sum of 191 and a difference of 63

Step-by-step explanation:

a+b=191

a-b=63

i sum these

a+b+a-b=191+63

2a=254

a=254/2

a=127

b=191-127

b=64

127 and 64

Step-by-step explanation:

To solve this, we can set up a system of equations.

We can name the first number x and the second number y.

x+y=191

x-y=63

We can use elimination to eliminate the y variable.

We do this by adding the equations together

  x+y=191

+ x-y=63

2x=254

Divide both sides by 2.

x=127

Now we can plug that in to find y.

x+y=191

127+y=191

Subtract 127 from both sides.

y=64

So our two numbers are 127 and 64.

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of

4

step-by-step explanation: