A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a speed of 10.0
meters/second. What is the emf produced?
OA.
10.65 volts
OB.
9.35 volts
C.
0.90 volts
OD
4.4 volts

Given:

length of the wire = 0.20 meters

magnetic field strength = 0.45 newtons/amperes meter

speed = 10.0 meters per second

emf = B * l * v 

B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds

emf = 0.90 volts

The emf produced is 0.90 volts.

Step-by-step explanation:

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

16

step-by-step explanation: