What is the probability of rolling a die 6 times and getting the numbers 1, 2, 3, 4, 5, 6 in that order? Select the best answer from the choices provided.
A. 0.001389
B. 0.000129
C. 0.000021
D. 0.0000038

C. 0.000021

Step-by-step explanation:

Each roll of the die is an independent event.

The probability of rolling a 1, then a 2, then a 3, then a 4, then a 5, then a 6 is the product of the 6 individual probabilities.

Probability of rolling a 1:

There are 6 possible outcomes, rolling 1, 2, 3, 4, 5, or 6.

There is one desired outcome, rolling a 1.

p(1) = 1/6

Probability of rolling a 2:

Similar to rolling a 1, there is 1 desired outcome,rolling a 2, out of 6 possible outcomes.

p(2) = 1/6

The same is true for rolling a 3, 4, 5, or 6. Each one has a probability of 1/6.

p(1, 2, 3, 4, 5, 6, in that order) = p(1) * p(2) * p(3) * p(4) * p(5) * p(6)

= (1/6)^6

= 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

= 1/46,656

= 0.000021433

C. 0.000021

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

10 you would take 50/ .2

step-by-step explanation: