I NEED HELP PLEASE! :)
Are the two lines parallel, perpendicular, or neither? Explain your answer. Show work needed to answer the question.
3x+7y=15
7x-3y=6

Perpendicular

Step-by-step explanation:

To tell if the lines are perpendicular/parallel, you must look at the slope, but in this case, you must first get y by itself, like so:

3x + 7y = 15

-3x           - 3x

___________

7y = -3x + 15

Divide both sides by 7:

y =

Now the other equation:

7x - 3y = 6

-7x         -7x

_________

-3y = -7x + 6

Divide both sides by -3:

y =

You can see that the lines are perpendicular because the slopes ( and ) are opposite reciprocals.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this