(11+i)^2

please help!

121 + 22i - 1

Step-by-step explanation:

Expand:

(11 + i)² = (11 + i)(11 + i)

Note that:

i² = -1

Use FOIL method. Multiply first terms, outside terms, inside terms, then the last two terms:

(11)(11) = 121

(11)(i) = 11i

(i)(11) = 11i

(i)(i) = -1

Combine like terms:

121 + 11i + 11i - 1

121 + (11i + 11i) - 1

121 + 22i - 1

121 + 22i - 1 is your answer.

~

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions