Show that (x+1)(x+3)(x+5) can be written in the form ax^3+bx^2+cx+d where a, b and c are all positive integers, and d is a negative integer

x^3+9x2+23x+15

Step-by-step explanation:

Just Expand the brackets

(x^2+4x+3)(x+5)

x^3+9x2+23x+15

Hope you understood(give me brainliest answer) ;)

for this case we must apply distributive property to the following expression:

the distributive property states that:

then, when applying the property we have to multiply the -2 for each term within the parenthesis:

3000000000000000000000