The number of entrees purchased in a single order at a Noodles & Company restaurant has had a historical average of 2 entrees per order. On a particular Saturday afternoon, a random sample of 46 Noodles orders had a mean number of entrees equal to 2.4 with a standard deviation equal to 1.07. At the 2 percent level of significance, does this sample show that the average number of entrees per order was greater than expected? (a) Choose the correct null and alternative hypotheses. H0: μ = 2 vs. H1: μ < 2 H0: μ = 2 vs. H1: μ > 2 H0: μ = 2 vs. H1: μ ≠ 2 a b c (b-1) Calculate the t statistic. (Round your answer to 2 decimal places.) tcalc (b-2) Find the p-value. (Round your answer to 3 decimal places.) p-value (c) Choose the correct conclusion. Because the p-value is greater than 0.02, we conclude that there is no evidence to indicate a significant increase in the average number of entrees per order. Because the p-value is less than 0.02, we conclude that there is evidence to indicate a significant increase in the average number of entrees per order.

The length of the largest fish is 967.74 times greater than the length of the smallest fish. select a variable expression that shows the length of the largest fish, if 8 is the length of the smallest fish. a. s + 967.74 b. \[ \frac{967.74}{s} \] c. 967.74 - s d. 967. 74s

Can someone me out here and the tell me the greatest common factor

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.