The paper cup is 9 cm tall and the circular opening has a radius of 2.5 cm.

What is the minimum amount of paper needed to make the paper cup to the nearest whole cm² assuming no overlap in the paper?

181cm^2

Step-by-step explanation:

The minimum amount of paper needed to make the cup to the nearest whole number will be = to the surface area of the cylinder = A=2πrh+2πr2.

Where π= 22/7, r = 2.5cm, h = 9cm

A = 2×22/7×2.5×9+2×22/7×2.5×2.5

A= 141.428+39.285

A= 180.713

A = 181cm^2

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

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