time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)
Answer from: Quest
x = 3 ± √(5+y)
Answer from: Quest
hard
step-by-step explanation:
Answer from: Quest
6^2 or 36
step-by-step explanation:
6000n
6×1000n
6×10^3 n
so we need 6n need to be a perfect cube
so n has to be 6^2 so that 6n is 6^3
what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube
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