Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag? Wh

Complete question:

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

1 2 3 4 5 6

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered three from the second bag?

1/36

Step-by-step explanation:

Number of tiles in each bag = 6

Probability of drawing tile numbered 2 from the first bag and the tile numbered 3 from the second

Probability of drawing number 2 from first bag :

P(numbered 2) = (required outcome / possible outcome)

P(numbered 2) = 1/6

Probability of drawing number 2 from first bag :

P(numbered 3) = 1/6

Since they are independent events :

P(drawing 2 from bag one and 3 from bag 2) :

1/6 × 1/6 = 1/36

good job you smart son of a gun you are smarter that einstein. 7