Find the sum. Write your answer in standard form.
( 4x3 + 2x + 6) + (2x3 – x? + 2)
The sum is

(4x3+2x+6)+(2x3-x2+2)

Final result :

6x3 - x2 + 2x + 8
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 2 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((4•(x3))+2x)+6)+((2x3-x2)+2)
Step 2 :

Equation at the end of step 2 :

((22x3 + 2x) + 6) + (2x3 - x2 + 2)
Step 3 :

Checking for a perfect cube :

3.1 6x3-x2+2x+8 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 6x3-x2+2x+8

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 2x+8
Group 2: 6x3-x2

Pull out from each group separately :

Group 1: (x+4) • (2)
Group 2: (6x-1) • (x2)