Find the perimeter of the stage shaped like a semi-circle (shown below), rounded to the nearest tenth of a foot.
20 ft
82.8 ft.
31.4 ft.
51.4 ft
62.8 ft.

Step-by-step explanation:

Hello there, because you did not attached the photo or the information of the diameter of the circle, so I will solve this type of question under a general form

Let's assume d is the diameter of the circle

=> the perimeter of the circle is: dπ

=> the perimeter of the half arc of a circle

= 1/2 perimeter of the circle

= 1/2dπ

Hence, the perimeter of the stage shaped like a semi-circle:

=  the perimeter of the half arc of a circle + the diameter

=  1/2dπ + d

= 3/2dπ

Just substitute d into the above expression, you will find out the answer.

Hope it will find you well.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

what is all that apply?