Find the rule for g−1(x).

a) g(x)=9−x^2 Domain: (x≤0)

g^-1(x) = ?

-1/3

Step-by-step explanation:

anything to the power of a negative number is the fraction 1/x

g(x)^-1 = (1/g(x))

factoring would be of perfect squared but since the x is negative it would be the ex's changing value and not the integer

9-x²= (-x+3)(x+3)

in solving both one is x=3 and x=-3, x=3 does not work with the set domain

x<0=\=3

however x=-3 does. this would be your x in the equation 1/x

x<0=-3