PLZ HELP! I am stuck on his question.
The ages of two exercise groups at a local fitness center are listed below.
Group A: 37 36 32 41 42 36 44 45
Group B: 26 40 38 36 42 40 40 36
Which statement about the data is true?
The mean age is the same for both groups
The range of ages is greater in Group A than in Group B
The mode of the ages for both groups is 36
The median age is the same for both groups

The median age is the same for both groups

Step-by-step explanation:

Group A:

37, 36, 32, 41, 42, 36, 44, 45

32, 36, 36, 37, 41, 42, 44, 45

Mean: (32+36+36+37+41+42+44+45)÷8=39.125

Range: 45-32=13

Mode: 36

Median: (41+37)÷2=39

Group B:

26, 40, 38, 36, 42, 40, 40, 36

26, 36, 36, 38, 40, 40, 40, 42

Mean:  (26+36+36+38+40+40+40+42)÷8=37.25

Range: 42-26=16

Mode: 40

Median: (40+38)÷2=39

Only the median in both groups are the same.

3rd choice:

Mode for A = 36. Mode for B = 36.

Step-by-step explanation:

Group A: 37 36 32 41 42 36 44 45

Mean age = 313 / 8 = 39.1

Group B: 26 40 38 36 42 40 40 36

Mean age = 298 / 8 = 37.3.

Range for Group A = 45 - 32 = 13

Range for Group B = 42 - 26 = 16.

Both  A and B have 2 instances of age 36.

Mode for A = 36. Mode for B = 36.

3x3 = 9 and 2x2 = 4

step-by-step explanation:

step-by-step explanation: