In a city school of 1200 students 42% of the students are on the honorable 64% have a part time job and 28% are on the honor roll and have a part-time job what is the probability that a randomly selected student is on the honor roll given that the student has a part time job

And replacing we got:

And the probability required for this case is 0.4375

Step-by-step explanation:

For this case we define the following events:

H = represent that the student is honorable

P= represent that the student have a part time job

And we have the following probabilities:

And we want to find this probability:

And we can use the following probability:

And replacing we got:

And the probability required for this case is 0.4375

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true