The line segments that connect 2nd base to 1st base' & 2nd base to 3rd base form a right angle. Marcus on 3rd base and he is 90ft from Jean who is on 2nd base. Jean is 90ft from Joel who is on 1st base. How far, in feet, is Marcus from Joel?

A. 45

B. 90

C. 90√2

D. 90√3

The correct answer is option C; 90√2

Step-by-step explanation: The line segments are labelled as base 1, base 2 and base 3 respectively. This we shall call point 1, point 2 and point 3. These three points form a right angle. Also we have been told that Marcus is on point 3 and Jean is on point 2. They are both 90 feet apart. Also Joel is on point 1 and he is 90 feet away from Jean. The unmeasured distance therefore is from point 1 to point 3, which is the distance from Joel to Marcus (or Marcus to Joel).

The distance from point 1 to point 3 is the hypotenuse of the right angled triangle derived. Using the Pythagoras' theorem, the distance from  Joel to Marcus (or JM) is calculated as follows;

JM² = JC² + JL²

Where JM is the distance between Joel and Marcus (hypotenuse), JC is the distance from Jean to Marcus and JL is the distance from Jean to Joel.

JM² = 90² + 90²

JM² = 8100 + 8100

JM² = 16200

Add the square root sign to both sides of the equation

√JM = √16200

JM = √100*√81*√2

The right hand side of the equation can be further solved as

JM = 10*9*√2

JM = 90√2

Therefore the distance between Marcus and Joel is calculated as 90√2 feet

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