The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached the
spring stretches 9 centimeters. Which equation relates the mass of the object, m, and the length of the spring, s?
m
10
10
S.
m
3
0 m
ma
30

We have been given that the length (s) of a spring varies directly with me mass (m) of an object. We are asked to find the equation that represents the relation, when a 30-gram object is attached the  spring stretches 9 centimeters.

We know that two directly proportional quantities are in form , where y is directly proportional to x and k is constant of proportionality.

Let us find constant of proportionality for our relation.

Therefore, our required equation would be .

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length