A device in your school Lab releases gas at a rate of, which means 0.25 of a liter of gas is released every second. The density of the gas is, which means that there are 4.3 grams of the gas in one liter. Set up the calculation to find the number of seconds it will take for the device to release 154 grams of the gas.

Drag each tile to the correct location. The tiles can be used more than once.

143.26 sec

Step-by-step explanation:

Density = 4.3 g/l

Volume flow rate = 0.25 l/s

Mass flow rate = density x volume flow rate

= 4.3 x 0.25 = 1.075 g/s

This means 1.075 grams of the gas is released in 1 sec, therefore,

Time taken for leakage of 154 g of gas is

t = 154/1.075 = 143.26 sec

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: