A circular hot spring has a diameter of 76 meters. Over time, the diameter of the spring decreases by 4 meters. By how many square meters does the area of the hot spring decrease? Use 3.14 for Pi.

( ANSWER QUICK , had to repost since yall aint responding )

And the answer has to be in centimeters.

Step-by-step explanation:

The formula for calculating the area of the circular hot spring = or

Initial area of the spring with diameter of 76metres is as shown

If the diameter of the spring decreases by 4 meters over time, the new diameter after decrease will be 76meters less 4 meters which is 72metres.

New area;

Decrease in area = 1444πm²-1296πm²

Decrease in area = 148πm²

= 370.53m²

since  1m²=10⁴cm²

then 370.53m² = 370.52*10⁴cm²

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

y -5 = (-1/4)(x + 8)

step-by-step explanation: