Esther cut a square paper vertically to make two rectangle pieces. Each rectangle had a perimeter of 63 inches.

How long is each side of the original square paper?

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Side of the square paper = 21 inches

Step-by-step explanation:

Let the square paper is having measure of each side = a inches

Esther cut this square piece into two pieces.

Let the other side of one rectangle piece = x inches

Perimeter of this piece = 2(a + x) inches

Similarly dimensions of the other rectangular piece will be = a inches × (a - x) inches

Perimeter of this piece = 2[a + (a - x)]

Since both the rectangular pieces have the same perimeter = 63

So, 2(a + x) = 2[a + (a - x)] = 63

2(a + x) = 2(2x - x)

a + x = 2a - x

2a - a = 2x

a = 2x

x =

Therefore, Perimeter = 2(a + x) = 2(a + ) = 63

= 63

3a = 63

a = 21

Therefore, measure of the sides of the square is 21 inches.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )