6x^2 - 19x + 10
Factor

(2x-5)(3x-2)

Step-by-step explanation:

1)When factoring quadratic equations in for ax²+bx+c you need to separate the b term in a way that the two addends you separate it by should equal a•c. Just do trial and error. In this case you should get -4 and -15. Your separated equation should be:

6x²-4x-15x+10

2)now factor out a common factor from the first two terms and one from the last two terms you should have:

2x(3x-2)-5(3x-2)

3)finally rewrite this equation into two separate factors and you have your answer.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.