4. There are 10 cheerleading squads performing in a competition. The
order of the performances is determined at random. What is the
probability that your squad performs first and your friend's squad performs
second?

0.011 or 1/90

Step-by-step explanation:

Since the order of the performances is determined at random the probability of each squad is constant that 1/10

The probability of your squad is 1/10

Given that the first selected was yours (1/10) nine squads are left . Therefore the probability of your friends squad is 1/9.

Hence  the probability that your squad performs first and your friend's squad performs second is (1/10 * 1/9) 1/90 or 0.011

answer: the common difference is -0.10

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: