units greater than the width.
Mathematics, 21.05.2020 08:58 Fhalcon543
A rectangle has an area of 40 square units. The length is 6
units greater than the width.
What are the dimensions of the rectangle?
8 by 5
10 by 4
11 by 9
013 by 7
Answers: 3
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Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
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A rectangle has an area of 40 square units. The length is 6
units greater than the width.
units greater than the width.
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