16,500+ 1020x
The function Y=
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models y, the average annual cost in dollars of owning a car for x years. Which statement
16,500+ 1020x
best explains why the graph of y=
should have a vertical asymptote at x = 0?
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O The value of the car decreases over time.
The value of the car will never dip below $0.
The time the car is owned is greater than 0.
O The initial cost of the car is greater than $0.

C. The time the car is owned is greater than 0

Function:

Where x denotes years

y denotes annual cost

We are given that the graph of the given equation should have vertical asymptote at x =0

Refer the attached graph .

Since with increase in the time the cost (y) decreases

So, the time must be greater than 0 So, that the change in the cost appears .

So, the graph of the given equation should have vertical asymptote at x =0 because The time the car is owned is greater than 0.

Hence Option C is correct : The time the car is owned is greater than 0.

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.