How many solutions does this quadratic equation have?
6p^2-7p+5=0

It has no real solution.

Step-by-step explanation:

6p^2 − 7p + 5 = 0

For this equation: a = 6, b = -7, c = 5

6p^2+ −7p + 5 = 0

Step 1: Use quadratic formula with a=6, b=-7, c=5.

p = -b ± √b^2 - 4ac/2a

p = -(-7) ± √(-7)^2 - 4(6)(5)/2(6)

p = 7 ± √-71/12

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}

0,0

step-by-step explanation: