Find the equation of a line parallel to 2x-3y=9 that passes through the point (1, -3)

y = 2/3x - 11/3

Step-by-step explanation:

2x-3y=9

Rearrange to find the parallel gradient:

-3y = -2x+9

y = 2/3x -3

M(gradient) = 2/3

M(parallel gradient) = 2/3

Substitute the gradient and the points point A and B into the equation :

y-b = m(x-a)

y - (-3) = 2/3(x-1)

3y + 9 = 2x -2

3y = 2x -11

y = 2/3x - 11/3

if you use photomath right away it will give you the answer not like this app that you have to wait for people.

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.