The following table shows the salary of 7 people in an office last year. Name Income Andy £13500 Bevan £27500 Cheryl £13250 Deva £75000 Elliott £18750 Frankie £27500 Grace £15000 a) Work out the mean income to 2 DP. b) Deva was given a large bonus for 30 years service. Excluding Deva's income, what was the mean income for the remaining 6 workers to 2 DP?

The mean income to 2 DP is £27,214.29.

The mean income excluding Deva's salary is  £19,250.

Mean income is the average of the income of the seven individuals. It is determined by adding the income of the individuals and dividing it by the total number of people.  

Mean = sum of the salaries  / total number of people

Sum of the salaries = £13,500 + £27,500 + £13,250 + £75,000 + £18,750 + £27,500 + £15,000 = £190,500

Mean = £190,500 / 7 = £27,214.29

Mean excluding Deva's salary:

Sum of salaries = £13,500 + £27,500 + £13,250 + £18,750 + £27,500 + £15,000 = £115,500

Mean = £115,500 / 6 = £19,250

To learn more about mean, please check: link

A.) £27,214.29

B.) £19,250

Step-by-step explanation:

Given the following :

Andy £13500

Bevan £27500

Cheryl £13250

Deva £75000

Elliott £18750

Frankie £27500

Grace £15000

Mean income = (total sum of salaries / number of workers)

Mean income = £(13500 + 27500 + 13250 + 75000 + 18750 + 27500 + 15000) / 7

Mean income = (£190,500 / 7) = £27,214.286

B.) mean income excluding Deva's salary:

Mean income = Mean income = £(13500 + 27500 + 13250 + 18750 + 27500 + 15000) / 7

Mean income = £115,500 / 6

Mean income = £19,250

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.