Will do a brianly. What sequence of transformations, when applied to △ABC, shows that △ABC is similar to △A′B′C′?

A. dilation with respect to the origin by a scale factor of 12 followed by a translation of 2 units right.

B. translation of 2 units right followed by a dilation with respect to the origin by a scale factor of 12.

C. translation of 2 units left followed by a dilation with respect to the origin by a scale factor of 12.

D. dilation with respect to the origin by a scale factor of 2 followed by a translation of 2 units left.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.

arc length = radius * x ( in radians)

6 * pi = 18 * x

divide by 18 on each side

6 pi / 18 = x

pi/3 = x

the angle is pi / 3 radians

or   60 degrees