A rectangle with perimeter 30 in. has length 10 in. What is the area of the rectangle?

Length of rectangle = 10in.

Breadth " " =x

Perimeter= 2( l+b)=30in.

Perimeter=2(10+b)=30in.

=(10+b)=30/2=15

=b=15-10

Breadth=5in.

50 in²

Explanation: Remember that the formula for the area of a rectangle is length · width so we need to find the width of the rectangle.

To find the width of the rectangle, let's use our formula

for the perimeter of a rectangle which is 2l + 2w.

Since we know that the perimeter of the rectangle is 30 inches and the length of the rectangle is 10 inches, we have 30 = 2(10) + 2w.

Simplifying on the right side gives us 30 = 20 + 2w.

Now subtract 20 from both sides to get 10 = 2w.

Finally, dividing both sides by 2, we find that 5 = w.

So the width of the rectangle is 5 inches and remember

that the length of the rectangle is 10 inches.

So the area of the rectangle, l · w, is 10 · 5 or 50 in².

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: