Reflect ΔECD over segment AC. This establishes that . Then, translate point E' to point A. This establishes that . Therefore, ΔACB ~ ΔECD by the AA similarity postulate.
a. ∠ABC ≅ ∠E'D'C'; ∠E'D'C' ≅ ∠ABC
b. ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC
c. ∠ACB ≅ ∠E'C'D'; ∠E'D'C' ≅ ∠ABC
d. ∠ABC ≅ ∠E'D'C'; ∠D'E'C' ≅ ∠BAC

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

b.my answer is b.

brainliest

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15