The four corners of a square chessboard touch the edge of a round table. The length of the chessboard is 1 foot. Find the length of the radius of the table

Step-by-step explanation:

Given: Four corners of a square chessboard touch the edge of a round table. The length of the chessboard is 1 foot.

To find: length of the radius of the table

Solution:

Diameter of the round table is equal to the diagonal of a square chessboard.

Diagonal of a square chessboard = × side of the square chessboard

Here, side of a square chessboard = 1 foot

So,

Diagonal of a square chessboard = × 1 = foot

Diameter of the round table = Diagonal of a square chessboard = foot

Radius of the round table = Diameter of the round table/2

=

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9

i need a picture

step-by-step explanation: