The graph of which function has an axis of symmetry at x=-1/4?

2x^2 + 1x + C

Step-by-step explanation:

The three coefficients of a quadratic function are a, b and c, where a is the coefficient of the x^2 term.

The equation of the axis of symmetry is

          -b

x =    and   here we are told that this x is -1/4.

          2a

From this info we can assume that a = 2 and that b = 1

and so the function is likely 2x^2 + 1x + C, where C is a constant.  Doesn't matter what C is in this case.

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.