The graph below shows the height of a projectile t seconds after it is launched. If acceleration due to gravity is -16 ft/s2
which equation models the height of the projectile correctly?
h(t) = at2 + vt + h0

Correct option: fourth one -> h(t) = -16t2 + 32v + 5

Step-by-step explanation:

To find the equation h(t) we need to find the values of a, v and h0.

The value of a is already given (a = -16).

Now, we just need to use two of the three points given to find the other parameters:

point (1,21): t = 1 and f(t) = 21:

21 = -16 + v + h0

point (0,5): t = 0 and f(t) = 5

5 = 0 + 0 + h0

h0 = 5

Using this value of h0 in the first equation, we have:

21 = -16 + v + 5

v = 21 + 16 - 5 = 32

So the equation is:

h(t) = -16t2 + 32v + 5

Correct option: fourth one.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

da freeck kinda math is this just drop out

step-by-step explanation: