What are the roots of the equation

Step-by-step explanation:

it would be 2±√26÷3 its C

C

Step-by-step explanation:

3x^2+10=4x

3x^2-4x+10=0      <-- Subtract 4x from both sides

Quadratic Formula:

x = -b±sqrt(b^2-4ac)/2a

x = 4±sqrt[-4^2-4(3)(10)]/2(3)   <-- Substitute

x = 4±sqrt(-104)/6

x = 4±isqrt(104)/6   <-- Take out sqrt -1 which is i

x = 4±isqrt(26*4)/6    <-- Simplify sqrt  

x = 4±2isqrt(26)/6   <-- Divide numerator and denominator by GCF

x = 2±isqrt(26)/3   <-- Thus, option C is the correct answer

i believe it is d.) buddhism and e.) hinduism