How many times more likely is it for a student who took Spanish to have traveled to a Spanish - speaking country than a student who did not take Spanish ?

The complete question is:

The diagram below represents three groups of students:

S (blue and green): The set of students who took a Spanish class.

T (green and orange): The set of students who traveled to a Spanish-speaking country.

D (red and orange): The set of students who did not take a Spanish class. Each block represents one student.

How many times more likely is it for a student who took Spanish to have traveled to a Spanish-speaking country than a student who did not take Spanish?

a. It is 2.3 times as likely.

b. It is 3.3 times as likely.

c. It is 23 times as likely.

d. It is 30 times as likely.

CORRECT OPTION IS B

It is 3.33 times as likely

Step-by-step explanation:

The set of students who took Spanish class = 24

The set of students who travels to Spainish-speaking country = 80

The probability of students traveling to Spainish-speaking country given that they took Spanish Class is 8/24 = 1/3

The probability of students traveling to Spainish-speaking country given they did not take Spanish class is 8/80 = 1/10

Now, the probability that a student travels to a Spainish-speaking country given that the student took Spanish class is 1/3 ÷ 1/10 = 10/3 = 3.33

That is it is 3.33 times as likely

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

19

step-by-step explanation: