A circular flower bed is 19 m in diameter and has a circular sidewalk around it that is 4 m wide. Find the area of the sidewalk in square meters. Use 3.14 for pi.
The area of the sidewalk is
msquared.
(Round to the nearest whole number as needed.)
PLEASE HELP

289 m²

Step-by-step explanation:

First find the area of the flower bed

A=πr²= (3.14)(9.5)² = 283.385

Then get the area of everything including the sidewalk

A=πr²= (3.14)(13.5)² = 572.265

Then subtract and you'll get the area of just the sidewalk

572.265 - 283.385 = 288.88m²

289 m^2

Step-by-step explanation:

The diameter is 19 for the flowerbed, so the radius is

r = d/2 = 19/2 =9.5

We add the sidewalk

9.5+4 = 13.5

So the radius of the flowerbed and sidewalk is 13.5 m

We need to find the area of the flowerbed and sidewalk

A = pi r^2 = 3.14 ( 13.5)^2 = 572.265

The area of the flowerbed is

A = pi r^2 =   3.14 ( 9.5)^2 = 283.385

Subtract the two to find the area of the sidewalk

572.265-283.385 =288.88

Rounding to the nearest whole number

289 m^2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: